What is (\partial)/(\partial y)(tan(3x-4y)) ?

The answer to (\partial)/(\partial y)(tan(3x-4y)) is -4sec^2(3x-4y)

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(\partial)/(\partial y)(tan(3x-4y))

\frac{\partial}{\partial y} (tan (3 x - 4 y))

- 4 sec^{2} (3 x - 4 y)

Solution steps

\frac{\partial}{\partial y} (tan (3 x - 4 y))

Treat

x

as a constant

Apply the chain rule:

sec^{2} (3 x - 4 y) \frac{\partial}{\partial y} (3 x - 4 y)

= sec^{2} (3 x - 4 y) \frac{\partial}{\partial y} (3 x - 4 y)

\frac{\partial}{\partial y} (3 x - 4 y) = - 4

= sec^{2} (3 x - 4 y) (- 4)

Simplify

= - 4 sec^{2} (3 x - 4 y)

\int (x - 1)^{n} d x

\int \frac{1}{- x ^{2} + 1} d x

\frac{d}{d x} (9 x ln (x))

2^{- x}

x \to 400 - lim (x)

What is (\partial)/(\partial y)(tan(3x-4y)) ?
The answer to (\partial)/(\partial y)(tan(3x-4y)) is -4sec^2(3x-4y)