What is the sum from n=0 to infinity of (-1)^n*1^n ?

The sum from n=0 to infinity of (-1)^n*1^n is diverges

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sum from n=0 to infinity of (-1)^n*1^n

n = 0 \sum \infty (- 1)^{n} \cdot 1^{n}

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} \cdot 1^{n}

Simplify

= n = 0 \sum \infty (- 1)^{n}

Apply Series Geometric Test:

diverges

= diverges

n = 3 \sum \infty \frac{1}{( n ^{2} - 4 )}

n = 0 \sum \infty \frac{5 ^{n}}{n ^{2}}

n = 0 \sum \infty \frac{8}{( 1 - 7 n )}

n = 1 \sum \infty 53 (\frac{1}{2})^{n}

n = 0 \sum \infty \frac{2 n}{n ^{2} + 4}

What is the sum from n=0 to infinity of (-1)^n*1^n ?
The sum from n=0 to infinity of (-1)^n*1^n is diverges