What is the sum from n=1 to infinity of (ln(8n))/n ?

The sum from n=1 to infinity of (ln(8n))/n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (ln(8n))/n

n = 1 \sum \infty \frac{ln ( 8 n )}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{ln ( 8 n )}{n}

Apply Series Integral Test:

diverges

= diverges

k = 0 \sum \infty 9 \cdot (\frac{3}{5})^{k}

n = 2 \sum \infty (0.2)^{n}

n = 0 \sum \infty cos (4 n)

n = 0 \sum \infty e^{- 10 n}

k = 1 \sum \infty \frac{2 ^{k}}{( k ) !}

What is the sum from n=1 to infinity of (ln(8n))/n ?
The sum from n=1 to infinity of (ln(8n))/n is diverges