What is the sum from n=0 to infinity of e^{-18n} ?

The sum from n=0 to infinity of e^{-18n} is converges

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sum from n=0 to infinity of e^{-18n}

n = 0 \sum \infty e^{- 18 n}

converges

Solution steps

n = 0 \sum \infty e^{- 18 n}

Apply Series Integral Test:

converges

= converges

k = 1 \sum \infty (\frac{2}{3})^{k}

n = 1 \sum \infty (- 0.01 + 1)^{n}

n = 0 \sum \infty \frac{n}{5 n - 3}

n = 1 \sum \infty (2)^{n}

n = 0 \sum \infty 8 - 5 n^{4}

What is the sum from n=0 to infinity of e^{-18n} ?
The sum from n=0 to infinity of e^{-18n} is converges