What is the derivative of sqrt(x)+\sqrt[4]{x} ?

The derivative of sqrt(x)+\sqrt[4]{x} is 1/(2sqrt(x))+1/(4x^{3/4)}

What is the first derivative of sqrt(x)+\sqrt[4]{x} ?

The first derivative of sqrt(x)+\sqrt[4]{x} is 1/(2sqrt(x))+1/(4x^{3/4)}

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derivative of

\frac{1}{2 x} + \frac{1}{4 x ^{\frac{3}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{1}{4 x ^{\frac{3}{4}}}

\int \frac{x + 1}{x - 1} d x

tan (X)

\frac{\partial}{\partial x} ((x - 4)^{2})

\frac{\partial}{\partial x} (\frac{x}{z})

\frac{\partial}{\partial z} (7 x^{\frac{y}{z}})

What is the derivative of sqrt(x)+\sqrt[4]{x} ?
The derivative of sqrt(x)+\sqrt[4]{x} is 1/(2sqrt(x))+1/(4x^{3/4)}
What is the first derivative of sqrt(x)+\sqrt[4]{x} ?
The first derivative of sqrt(x)+\sqrt[4]{x} is 1/(2sqrt(x))+1/(4x^{3/4)}