What is the sum from n=1 to infinity of cos((13)/n) ?

The sum from n=1 to infinity of cos((13)/n) is diverges

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sum from n=1 to infinity of cos((13)/n)

n = 1 \sum \infty cos (\frac{13}{n})

diverges

Solution steps

n = 1 \sum \infty cos (\frac{13}{n})

Apply Series Divergence Test:

diverges

= diverges

n = 3 \sum \infty \frac{n}{3 ^{n}}

n = 1 \sum \infty (\frac{12}{7})^{n}

n = 1 \sum \infty n (\frac{5}{6})^{n - 1}

n = 4 \sum \infty \frac{1}{n ^{5}}

n = 1 \sum \infty (- \frac{5}{8})^{n - 1}

What is the sum from n=1 to infinity of cos((13)/n) ?
The sum from n=1 to infinity of cos((13)/n) is diverges