What is the sum from n=0 to infinity of (2^n)/(2n-1) ?

The sum from n=0 to infinity of (2^n)/(2n-1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (2^n)/(2n-1)

n = 0 \sum \infty \frac{2 ^{n}}{2 n - 1}

diverges

Solution steps

n = 0 \sum \infty \frac{2 ^{n}}{2 n - 1}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty 1 - \frac{1}{n + 1}

n = 1 \sum \infty \frac{1}{( 4 n + 3 ) ^{4}}

n = 2 \sum \infty 6 e^{- 3 n}

n = 0 \sum \infty n (e^{- n})

n = 1 \sum \infty \frac{n !}{10 9 ^{n}}

What is the sum from n=0 to infinity of (2^n)/(2n-1) ?
The sum from n=0 to infinity of (2^n)/(2n-1) is diverges