What is the sum from n=1 to infinity}(e^{(1/n) of)/n ?

The sum from n=1 to infinity}(e^{(1/n) of)/n is converges

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sum from n=1 to infinity}(e^{(1/n) of)/n

n = 1 \sum \infty \frac{e ^{(\frac{1}{n})}}{n}

converges

Solution steps

n = 1 \sum \infty \frac{e ^{\frac{1}{n}}}{n}

Apply Series Integral Test:

converges

= converges

n = 1 \sum \infty \frac{2 ^{n}}{n ^{1}}

k = 1 \sum \infty \frac{3}{k !}

n = 1 \sum \infty \frac{3}{2 + n}

n = 1 \sum \infty \frac{n !}{( 3 n ) !}

i = 0 \sum \infty i

What is the sum from n=1 to infinity}(e^{(1/n) of)/n ?
The sum from n=1 to infinity}(e^{(1/n) of)/n is converges