What is the sum from n=1 to infinity of (n^6)/(n^7) ?

The sum from n=1 to infinity of (n^6)/(n^7) is diverges

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sum from n=1 to infinity of (n^6)/(n^7)

n = 1 \sum \infty \frac{n ^{6}}{n ^{7}}

diverges

Solution steps

n = 1 \sum \infty \frac{n ^{6}}{n ^{7}}

Simplify

\frac{n ^{6}}{n ^{7}} : \frac{1}{n}

= n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= diverges

n = 1 \sum \infty \frac{4 n}{3 n + 1}

n = 1 \sum \infty \frac{n + 1}{3 - 2 n}

n = 1 \sum \infty \frac{1 1 ^{n}}{n !}

n = 0 \sum \infty \frac{i}{n ^{2}}

k = 1 \sum \infty (cos (14))^{k}

What is the sum from n=1 to infinity of (n^6)/(n^7) ?
The sum from n=1 to infinity of (n^6)/(n^7) is diverges