What is derivative of f(x)=e^{-3/(t^2)} ?

The answer to derivative of f(x)=e^{-3/(t^2)} is (dt)/(dx)=0

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derivative of f(x)=e^{-3/(t^2)}

derivative of

f (x) = e^{- \frac{3}{t ^{2}}}

\frac{d t}{d x} = 0

Solution steps

f (x) = e^{- \frac{3}{t ^{2}}}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{6 e ^{- \frac{3}{t ^{2}}} \frac{d t}{d x}}{t ^{3}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d}{d x} (cos (x) \cdot tan (x))

f (x) = 1 0^{x}

\int \frac{x ^{3} - 5 x ^{2} - x}{x ^{2}} d x

\frac{\partial}{\partial y} (x e^{y} cos (z) - z)

\int \frac{x}{144 x ^{2} - 1} d x

What is derivative of f(x)=e^{-3/(t^2)} ?
The answer to derivative of f(x)=e^{-3/(t^2)} is (dt)/(dx)=0