What is the sum from n=1 to infinity of 1/((n+1)^3) ?

The sum from n=1 to infinity of 1/((n+1)^3) is converges

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sum from n=1 to infinity of 1/((n+1)^3)

n = 1 \sum \infty \frac{1}{( n + 1 ) ^{3}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{( n + 1 ) ^{3}}

Apply Series Comparison Test:

converges

= converges

n = 1 \sum \infty 5 e^{- 0.5 n}

n = 0 \sum \infty \frac{7}{n + 3}

n = 1 \sum \infty \frac{2 n ^{3}}{n ^{4}}

n = 2 \sum \infty (1 + \frac{1}{2})^{- n}

n = 1 \sum \infty \frac{- 1}{n ^{2}}

What is the sum from n=1 to infinity of 1/((n+1)^3) ?
The sum from n=1 to infinity of 1/((n+1)^3) is converges