What is the sum from n=1 to infinity of (2n+3)/(n+1) ?

The sum from n=1 to infinity of (2n+3)/(n+1) is diverges

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sum from n=1 to infinity of (2n+3)/(n+1)

n = 1 \sum \infty \frac{2 n + 3}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n + 3}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty (\frac{1 + 5}{n})^{n}

n = 0 \sum \infty 2 (\frac{1}{3})^{n}

n = 1 \sum \infty \frac{17 n}{n !}

n = 9 \sum \infty \frac{n !}{n ^{n}}

n = 0 \sum \infty cos (5 n) π

What is the sum from n=1 to infinity of (2n+3)/(n+1) ?
The sum from n=1 to infinity of (2n+3)/(n+1) is diverges