What is the sum from n=0 to infinity of 1/(n+17) ?

The sum from n=0 to infinity of 1/(n+17) is diverges

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sum from n=0 to infinity of 1/(n+17)

n = 0 \sum \infty \frac{1}{n + 17}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{n + 17}

Apply Series Integral Test:

diverges

= diverges

k = 2 \sum \infty \frac{4}{7 ^{k}}

k = 1 \sum \infty (1)^{k}

n = 1 \sum \infty \frac{3 ^{n}}{1 2 ^{n}}

n = 1 \sum \infty \frac{4}{7 n - 1}

n = 9 \sum \infty \frac{4}{8 ^{n}}

What is the sum from n=0 to infinity of 1/(n+17) ?
The sum from n=0 to infinity of 1/(n+17) is diverges