What is the sum from n=1 to infinity of 6^{-2n} ?

The sum from n=1 to infinity of 6^{-2n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 6^{-2n}

n = 1 \sum \infty 6^{- 2 n}

converges

Solution steps

n = 1 \sum \infty 6^{- 2 n}

Apply Series Ratio Test:

converges

= converges

n = 1 \sum \infty 3 (- \frac{1}{7})^{3 n}

n = 2 \sum \infty \frac{n}{6 ^{n}}

y^{^{'}} = 3 x y + 5 y

sin (3 x) d x + 2 y cos^{3} (3 x) d y = 0

\frac{d y}{d x} = \frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )}

What is the sum from n=1 to infinity of 6^{-2n} ?
The sum from n=1 to infinity of 6^{-2n} is converges