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Popular >

2xy+6x+(x^2-9)y^'=0

Solution

2 x y + 6 x + (x^{2} - 9) y^{^{'}} = 0

Solution

y = \frac{c _{1}}{x ^{2} - 9} - 3

Solution steps

2 x y + 6 x + (x^{2} - 9) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9} - 3

y = \frac{c _{1}}{x ^{2} - 9} - 3

Graph

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Frequently Asked Questions (FAQ)

What is the solution for 2xy+6x+(x^2-9)y^'=0 ?
The solution for 2xy+6x+(x^2-9)y^'=0 is y=(c_{1})/(x^2-9)-3