What is (\partial)/(\partial x)(1/(t^2+1)) ?

The answer to (\partial)/(\partial x)(1/(t^2+1)) is 0

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(\partial)/(\partial x)(1/(t^2+1))

\frac{\partial}{\partial x} (\frac{1}{t ^{2} + 1})

0

Solution steps

\frac{\partial}{\partial x} (\frac{1}{t ^{2} + 1})

Treat

t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

y = \frac{2}{x ^{2}}, (2, \frac{2}{49})

x = y^{2} - 6 y, x = 3 y - y^{2}

\int x^{2} cos (n x π) d x

\int \frac{1}{y 5 y ^{2} - 3} d y

\int (x - 0.1)^{2} (x - 0.75)^{2} d x

What is (\partial)/(\partial x)(1/(t^2+1)) ?
The answer to (\partial)/(\partial x)(1/(t^2+1)) is 0