What is the solution for (dy)/(dx)=-2xy^4 ?

The solution for (dy)/(dx)=-2xy^4 is y=-1/(\sqrt[3]{3(-x^2+c_{1))}}

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(dy)/(dx)=-2xy^4

\frac{d y}{d x} = - 2 x y^{4}

y = - \frac{1}{3 3 ( - x ^{2} + c _{1} )}

Solution steps

\frac{d y}{d x} = - 2 x y^{4}

Solve separable ODE:

y = - \frac{1}{3 3 ( - x ^{2} + c _{1} )}

y = - \frac{1}{3 3 ( - x ^{2} + c _{1} )}

(y + y cos (x) y) d x + (x + x cos (x) y) d y = 0

(2 + x) y^{^{'}} - y = 0

x (1 + y^{2}) d x - y (1 + x^{2}) d y = 0

\frac{d x}{d t} = 125 - \frac{x}{100}

\frac{d Q}{d t} = 4 Q^{2} ln (t), Q (1) = - 1

What is the solution for (dy)/(dx)=-2xy^4 ?
The solution for (dy)/(dx)=-2xy^4 is y=-1/(\sqrt[3]{3(-x^2+c_{1))}}