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Popular >

y^'=e^{x-y},y(0)=0

Solution

y^{^{'}} = e^{x - y}, y (0) = 0

Solution

y = x

Solution steps

y^{'} (x) = e^{x - y}

Solve separable ODE:

y = x

y = x

Popular Examples

1-1/(y^2-4y+4)y^'=0

1 - \frac{1}{y ^{2} - 4 y + 4} y^{^{'}} = 0

y^'=(y^2+y^2cos(x))^2

y^{^{'}} = (y^{2} + y^{2} cos (x))^{2}

(dx)/(dt)=4(x^2+1),x(pi/4)=1

\frac{d x}{d t} = 4 (x^{2} + 1), x (\frac{π}{4}) = 1

(4x-8)dx-(6y-10)dy=0

(4 x - 8) d x - (6 y - 10) d y = 0

(dx)/(dt)=80-x/(100)

\frac{d x}{d t} = 80 - \frac{x}{100}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{x-y},y(0)=0 ?
The solution for y^'=e^{x-y},y(0)=0 is y=x