What is the solution for (dy}{dx}=\frac{20x^4)/y ?

The solution for (dy}{dx}=\frac{20x^4)/y is y=sqrt(8x^5+c_{1)},y=-sqrt(8x^5+c_{1)}

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(dy}{dx}=\frac{20x^4)/y

\frac{d y}{d x} = \frac{20 x ^{4}}{y}

y = 8 x^{5} + c_{1}, y = - 8 x^{5} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{20 x ^{4}}{y}

Solve separable ODE:

y = 8 x^{5} + c_{1}, y = - 8 x^{5} + c_{1}

y = 8 x^{5} + c_{1}, y = - 8 x^{5} + c_{1}

\frac{d y}{d x} = 0.2 x y

\frac{d y}{d x} = \frac{2 ( 1 + x )}{x y}

\frac{d y}{d x} (1 + x^{4}) - 3 x^{3} y = 0

y^{^{'}} = e^{x} cos^{2} (y)

5 x^{3} d y = \frac{x ^{4} \cdot e ^{3 x}}{y ^{2}} d x

What is the solution for (dy}{dx}=\frac{20x^4)/y ?
The solution for (dy}{dx}=\frac{20x^4)/y is y=sqrt(8x^5+c_{1)},y=-sqrt(8x^5+c_{1)}