What is the derivative of 2xy+y ?

The derivative of 2xy+y is 2(y+x(dy)/(dx))+(dy)/(dx)

What is the first derivative of 2xy+y ?

The first derivative of 2xy+y is 2(y+x(dy)/(dx))+(dy)/(dx)

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\frac{d}{d x} (2 x y + y)

2 (y + x \frac{d y}{d x}) + \frac{d y}{d x}

Solution steps

\frac{d}{d x} (2 x y + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x y) + \frac{d y}{d x}

\frac{d}{d x} (2 x y) = 2 (y + x \frac{d y}{d x})

= 2 (y + x \frac{d y}{d x}) + \frac{d y}{d x}

\frac{\partial}{\partial t} (s t)

f (x) = \frac{x ^{2}}{4 - x ^{2}}

\int cos^{5} (x s i) n^{4} x

w

\int 3 x^{\frac{5}{2}} d x

What is the derivative of 2xy+y ?
The derivative of 2xy+y is 2(y+x(dy)/(dx))+(dy)/(dx)
What is the first derivative of 2xy+y ?
The first derivative of 2xy+y is 2(y+x(dy)/(dx))+(dy)/(dx)