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Popular >

y^'=(2y^2)/(x^2)

Solution

y^{^{'}} = \frac{2 y ^{2}}{x ^{2}}

Solution

y = - \frac{x}{- 2 + c _{1} x}

Solution steps

y^{'} (x) = \frac{2 y ^{2}}{x ^{2}}

Solve separable ODE:

y = - \frac{x}{- 2 + c _{1} x}

y = - \frac{x}{- 2 + c _{1} x}

Popular Examples

((1+y))/(1-2y-y^2)(dy)/(dx)= 1/x

\frac{( 1 + y )}{1 - 2 y - y ^{2}} \frac{d y}{d x} = \frac{1}{x}

(dr)/(dt)=0.1872*r

\frac{d r}{d t} = 0.1872 \cdot r

(sqrt(1+x^2))/(1+y)(dy)/(dx)=-x

\frac{1 + x ^{2}}{1 + y} \frac{d y}{d x} = - x

y^'=(x^2-4)(3y+2)

y^{^{'}} = (x^{2} - 4) (3 y + 2)

(x^2+2x-1)(dy)/(dx)-(x+1)y=x+1

(x^{2} + 2 x - 1) \frac{d y}{d x} - (x + 1) y = x + 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2y^2)/(x^2) ?
The solution for y^'=(2y^2)/(x^2) is y=-x/(-2+c_{1)x}