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Popular >

y^'=-(xy)^2

Solution

y^{^{'}} = - (x y)^{2}

Solution

y = - \frac{3}{- x ^{3} + c _{1}}

Solution steps

y^{'} (x) = - (x y)^{2}

Solve separable ODE:

y = - \frac{3}{- x ^{3} + c _{1}}

y = - \frac{3}{- x ^{3} + c _{1}}

Popular Examples

y^'sin(2x)=ycos(2x)

y^{^{'}} sin (2 x) = y cos (2 x)

y^2(xdy-ydx)=3x^2(ydx-xdy)

y^{2} (x d y - y d x) = 3 x^{2} (y d x - x d y)

(\frac{x}{y}) y^{^{'}} + 2 y = 0

(dy)/(dx)=(y^2)*(x^2)

\frac{d y}{d x} = (y^{2}) \cdot (x^{2})

(dy)/(dx)=-y/(csc(x))

\frac{d y}{d x} = - \frac{y}{csc ( x )}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-(xy)^2 ?
The solution for y^'=-(xy)^2 is y=-3/(-x^3+c_{1)}