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Popular >

(x-1)dy+(y-2)dx=0

Solution

(x - 1) d y + (y - 2) d x = 0

Solution

y = \frac{c _{1}}{x - 1} + 2

Solution steps

(x - 1) d y + (y - 2) d x = 0

Solve separable ODE:

y = \frac{c _{1}}{x - 1} + 2

y = \frac{c _{1}}{x - 1} + 2

Popular Examples

y d x - x d y = 2 d y

(dy}{dx}=\frac{(1-2x))/y

\frac{d y}{d x} = \frac{( 1 - 2 x )}{y}

1/t y^'=6sin^2(y),y(1)=(5pi)/4

\frac{1}{t} y^{^{'}} = 6 sin^{2} (y), y (1) = \frac{5 π}{4}

y^'=(y*cos(x))/(1-2y)

y^{^{'}} = \frac{y \cdot cos ( x )}{1 - 2 y}

y^'= x/y ,y(1)=0

y^{^{'}} = \frac{x}{y}, y (1) = 0

Frequently Asked Questions (FAQ)

What is the solution for (x-1)dy+(y-2)dx=0 ?
The solution for (x-1)dy+(y-2)dx=0 is y=(c_{1})/(x-1)+2