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Popular >

dy=(1+4y^2)dx

Solution

d y = (1 + 4 y^{2}) d x

Solution

y = \frac{tan ( 2 x + c _{1} )}{2}

Solution steps

d y = (1 + 4 y^{2}) d x

Solve separable ODE:

y = \frac{tan ( 2 x + c _{1} )}{2}

y = \frac{tan ( 2 x + c _{1} )}{2}

Graph

Popular Examples

1/t y^'+2y=5t^3y

\frac{1}{t} y^{^{'}} + 2 y = 5 t^{3} y

sqrt(x)(dy)/(dx)=e^{8y+sqrt(x)}

x \frac{d y}{d x} = e^{8 y + x}

(dy)/(dx)-(5y)/(x^2)= 1/(x^2)

\frac{d y}{d x} - \frac{5 y}{x ^{2}} = \frac{1}{x ^{2}}

(1+y^2)dx-xdy=0

(1 + y^{2}) d x - x d y = 0

(dy)/(dx)e^{x+y}=x+1

\frac{d y}{d x} e^{x + y} = x + 1

Frequently Asked Questions (FAQ)

What is the solution for dy=(1+4y^2)dx ?
The solution for dy=(1+4y^2)dx is y=(tan(2x+c_{1}))/2