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Popular >

y^'-6y=0,y(-1)=10

Solution

y^{^{'}} - 6 y = 0, y (- 1) = 10

Solution

y = 10 e^{6 t + 6}

Solution steps

y^{'} (t) - 6 y = 0

Solve separable ODE:

y = 10 e^{6 t + 6}

y = 10 e^{6 t + 6}

Popular Examples

(dy)/(dx)=-(x+xy^2)/(y+x^2y)

\frac{d y}{d x} = - \frac{x + x y ^{2}}{y + x ^{2} y}

(4x^2y^2-x^2+4xy^2-x)dx+(2xy+x+2y+1)dy=0

(4 x^{2} y^{2} - x^{2} + 4 x y^{2} - x) d x + (2 x y + x + 2 y + 1) d y = 0

(dy)/(dx)=(3y)/(x^6)

\frac{d y}{d x} = \frac{3 y}{x ^{6}}

x y y^{^{'}} = - (1 + x^{2})

(dy)/(-y+10)=(dx)/(x+1)

\frac{d y}{- y + 10} = \frac{d x}{x + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'-6y=0,y(-1)=10 ?
The solution for y^'-6y=0,y(-1)=10 is y=10e^{6t+6}