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Popular >

y^'-y=2

Solution

y^{^{'}} - y = 2

Solution

y = e^{t + c_{1}} - 2

Solution steps

y^{'} (t) - y = 2

Solve separable ODE:

y = e^{t + c_{1}} - 2

y = e^{t + c_{1}} - 2

Popular Examples

(3x^2+2)^3y^'-xy^2=0,y(0)= 3/2

(3 x^{2} + 2)^{3} y^{^{'}} - x y^{2} = 0, y (0) = \frac{3}{2}

(dr)/(dt)=0.1872r

\frac{d r}{d t} = 0.1872 r

xtan(x)dx-ycos(x)dy=0

x tan (x) d x - y cos (x) d y = 0

(dy)/(dx)=(xy)/(x+1)

\frac{d y}{d x} = \frac{x y}{x + 1}

(dy)/(dt)=yt^3-1.5y

\frac{d y}{d t} = y t^{3} - 1.5 y

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=2 ?
The solution for y^'-y=2 is y=e^{t+c_{1}}-2