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Popular >

y^'=e^{3x-2y}

Solution

y^{^{'}} = e^{3 x - 2 y}

Solution

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

Solution steps

y^{'} (x) = e^{3 x - 2 y}

Solve separable ODE:

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

Popular Examples

(4x+xy^2)dx+(y+x^2y)dy=0

(4 x + x y^{2}) d x + (y + x^{2} y) d y = 0

y^'=-y^2,y(0)=1

y^{^{'}} = - y^{2}, y (0) = 1

a y d x + b x d y = 0

(dy)/(dx)+(x^2-4)y=x^2-4

\frac{d y}{d x} + (x^{2} - 4) y = x^{2} - 4

(dy)/(dx)=(sqrt(1-y^2))/(sqrt(1-x^2))

\frac{d y}{d x} = \frac{1 - y ^{2}}{1 - x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{3x-2y} ?
The solution for y^'=e^{3x-2y} is y=(ln(2/3 e^{3x}+c_{1}))/2