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Popular >

y^'=-ycos(x)

Solution

y^{^{'}} = - y cos (x)

Solution

y = e^{- s i n (x) + c_{1}}

Solution steps

y^{'} (x) = - y cos (x)

Solve separable ODE:

y = e^{- s i n (x) + c_{1}}

y = e^{- s i n (x) + c_{1}}

Popular Examples

y^'-2ty^3=0,y(2)=1

y^{^{'}} - 2 t y^{3} = 0, y (2) = 1

y^{^{'}} = \frac{7 y}{x}

(dy)/(dx)=(xsqrt(1-y^2))/(ysqrt(2x^2+1))

\frac{d y}{d x} = \frac{x 1 - y ^{2}}{y 2 x ^{2} + 1}

(dy)/(dx)=y(2+sin(x))

\frac{d y}{d x} = y (2 + sin (x))

y^'=(x^2+1)/(2-y)

y^{^{'}} = \frac{x ^{2} + 1}{2 - y}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-ycos(x) ?
The solution for y^'=-ycos(x) is y=e^{-sin(x)+c_{1}}