en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

dy=sqrt(1-4y^2)dx

Solution

d y = 1 - 4 y^{2} d x

Solution

y = \frac{sin ( 2 x + c _{1} )}{2}

Solution steps

d y = 1 - 4 y^{2} d x

Solve separable ODE:

y = \frac{sin ( 2 x + c _{1} )}{2}

y = \frac{sin ( 2 x + c _{1} )}{2}

Popular Examples

y^'=cos(x)tan(y)

y^{^{'}} = cos (x) tan (y)

(dy)/(dt)=(te^t)/(ysqrt(1+y^2))

\frac{d y}{d t} = \frac{t e ^{t}}{y 1 + y ^{2}}

y e^{y} d y + x d x = 0

(dy)/(dx)=(2x)/(-8y-10),y(0)=-8

\frac{d y}{d x} = \frac{2 x}{- 8 y - 10}, y (0) = - 8

y^{^{'}} = x e^{y - x}

Frequently Asked Questions (FAQ)

What is the solution for dy=sqrt(1-4y^2)dx ?
The solution for dy=sqrt(1-4y^2)dx is y=(sin(2x+c_{1}))/2