What is the solution for (dy)/(dx)=((2x(y-1)))/((x^2+3)) ?

The solution for (dy)/(dx)=((2x(y-1)))/((x^2+3)) is y=e^{c_{1}}x^2+3e^{c_{1}}+1

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(dy)/(dx)=((2x(y-1)))/((x^2+3))

\frac{d y}{d x} = \frac{( 2 x ( y - 1 ) )}{( x ^{2} + 3 )}

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( 2 x ( y - 1 ) )}{( x ^{2} + 3 )}

Solve separable ODE:

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

y = 2 x^{3} - x^{2} + 2 (1.3)

(10.4) (4.15)

\int \frac{e ^{x}}{1 + e ^{x}} d x

\int x^{2} + x + \frac{2}{x - 1} d x

y = \frac{x ^{2}}{x - 4}

What is the solution for (dy)/(dx)=((2x(y-1)))/((x^2+3)) ?
The solution for (dy)/(dx)=((2x(y-1)))/((x^2+3)) is y=e^{c_{1}}x^2+3e^{c_{1}}+1