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Popular >

xy^'+y=2

Solution

x y^{^{'}} + y = 2

Solution

y = - \frac{c _{1}}{x} + 2

Solution steps

x y^{'} (x) + y = 2

Solve separable ODE:

y = - \frac{c _{1}}{x} + 2

y = - \frac{c _{1}}{x} + 2

Popular Examples

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(8x+2)dx+(15y^2+3)dy=0,y(1)=1

(8 x + 2) d x + (15 y^{2} + 3) d y = 0, y (1) = 1

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2 x y d x - x d y = 0

(x^2+4)(dy)/(dx)+8xy=2x

(x^{2} + 4) \frac{d y}{d x} + 8 x y = 2 x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=2 ?
The solution for xy^'+y=2 is y=-(c_{1})/x+2