What is the solution for (dy}{dx}=\frac{y-1)/x ?

The solution for (dy}{dx}=\frac{y-1)/x is y=c_{1}x+1

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(dy}{dx}=\frac{y-1)/x

\frac{d y}{d x} = \frac{y - 1}{x}

y = c_{1} x + 1

Solution steps

\frac{d y}{d x} = \frac{y - 1}{x}

Solve separable ODE:

y = c_{1} x + 1

y = c_{1} x + 1

(2 x y - x + 2 y - 1) d x + (4 x^{2} y^{2} - x^{2} + 4 x y^{2} - x) d y = 0

\frac{d y}{d x} - 3 y - ln (3) = 0

\frac{d y}{d x} = - 4 x y + 8 x

(x ln (x)) y^{^{'}} = y

y^{^{'}} + y = 1, y (0) = 0

What is the solution for (dy}{dx}=\frac{y-1)/x ?
The solution for (dy}{dx}=\frac{y-1)/x is y=c_{1}x+1