What is the derivative of f(x)=1+x^2 ?

The derivative of f(x)=1+x^2 is 2x

What is the first derivative of f(x)=1+x^2 ?

The first derivative of f(x)=1+x^2 is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 1 + x^{2}

2 x

Solution steps

\frac{d}{d x} (1 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

\frac{d y}{d x} = x - 5

\int 3 3 x + 1 d x

\int x (x + 2)^{4} d x

f (x) = 4 x^{3} - 12 x^{2}, at x = - 2

\int sin (9 t) d t

What is the derivative of f(x)=1+x^2 ?
The derivative of f(x)=1+x^2 is 2x
What is the first derivative of f(x)=1+x^2 ?
The first derivative of f(x)=1+x^2 is 2x