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Popular >

y^'+x^2y=0

Solution

y^{^{'}} + x^{2} y = 0

Solution

y = e^{- \frac{x ^{3}}{3} + c_{1}}

Solution steps

y^{'} (x) + x^{2} y = 0

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + c_{1}}

y = e^{- \frac{x ^{3}}{3} + c_{1}}

Popular Examples

(dy)/(dx)=e^{-y}(2x-4),y(5)=0

\frac{d y}{d x} = e^{- y} (2 x - 4), y (5) = 0

(4x-1)dx-(6y-7)dy=0

(4 x - 1) d x - (6 y - 7) d y = 0

(2y^2+xy^3)dx+(2xy+x^2y^2)dy=0

(2 y^{2} + x y^{3}) d x + (2 x y + x^{2} y^{2}) d y = 0

y^{^{'}} - 2 x y = 3 y

y^{^{'}} = - \frac{x + 1}{y}

Frequently Asked Questions (FAQ)

What is the solution for y^'+x^2y=0 ?
The solution for y^'+x^2y=0 is y=e^{-(x^3)/3+c_{1}}