What is (\partial)/(\partial x)(3x^2-2y^2) ?

The answer to (\partial)/(\partial x)(3x^2-2y^2) is 6x

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(\partial)/(\partial x)(3x^2-2y^2)

\frac{\partial}{\partial x} (3 x^{2} - 2 y^{2})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 6 x - 0

Simplify

= 6 x

\frac{\partial}{\partial x} (ln (6 x^{2} + 7 y^{2} + 3))

\frac{\partial}{\partial x} (x^{4} y^{6} + 4 x^{7} y)

y^{^{'''}} - 3 y^{^{''}} + 3 y^{^{'}} - y = x - 3 e^{x}

t^{2} e^{2 t}

\int_{- 7}^{7} x 49 - x^{2} d x

What is (\partial)/(\partial x)(3x^2-2y^2) ?
The answer to (\partial)/(\partial x)(3x^2-2y^2) is 6x