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Popular >

y^'=x+xy

Solution

y^{^{'}} = x + x y

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Solution steps

y^{'} (x) = x + x y

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x+xy ?
The solution for y^'=x+xy is y=e^{(x^2)/2+c_{1}}-1