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Popular >

y^'-xy=0,y(0)=1

Solution

y^{^{'}} - x y = 0, y (0) = 1

Solution

y = e^{\frac{x ^{2}}{2}}

Solution steps

y^{'} (x) - x y = 0

Solve separable ODE:

y = e^{\frac{x ^{2}}{2}}

y = e^{\frac{x ^{2}}{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'-xy=0,y(0)=1 ?
The solution for y^'-xy=0,y(0)=1 is y=e^{(x^2)/2}