What is the solution for dy-dx+y=e^{4x} ?

The solution for dy-dx+y=e^{4x} is y=(e^{4x})/5+1+(c_{1})/(e^x)

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dy-dx+y=e^{4x}

d y - d x + y = e^{4 x}

y = \frac{e ^{4 x}}{5} + 1 + \frac{c _{1}}{e ^{x}}

Solution steps

d y - d x + y = e^{4 x}

Solve linear ODE:

y = \frac{e ^{4 x}}{5} + 1 + \frac{c _{1}}{e ^{x}}

y = \frac{e ^{4 x}}{5} + 1 + \frac{c _{1}}{e ^{x}}

\int_{- 2}^{3} \frac{49}{x ^{4}} d x

\int 2 tan^{3} (x) sec (x) d x

f (x) = \frac{6 x}{x + 1}

\frac{d}{d x} (\frac{1}{2 x ^{\frac{1}{2}}})

\int \frac{x ^{5}}{x ^{6} + 5} d x

What is the solution for dy-dx+y=e^{4x} ?
The solution for dy-dx+y=e^{4x} is y=(e^{4x})/5+1+(c_{1})/(e^x)