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Popular >

y^'=0.5y-250

Solution

y^{^{'}} = 0.5 y - 250

Solution

y = 2 e^{\frac{t + c _{1}}{2}} + 500

Solution steps

y^{'} (t) = 0.5 y - 250

Solve separable ODE:

y = 2 e^{\frac{t + c _{1}}{2}} + 500

y = 2 e^{\frac{t + c _{1}}{2}} + 500

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=0.5y-250 ?
The solution for y^'=0.5y-250 is y=2e^{(t+c_{1})/2}+500