What is the solution for (dy)/(dx)=(y-2)^4 ?

The solution for (dy)/(dx)=(y-2)^4 is y=-\sqrt[3]{1/(3(x+c_{1))}}+2

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(dy)/(dx)=(y-2)^4

\frac{d y}{d x} = (y - 2)^{4}

y = - 3 \frac{1}{3 ( x + c _{1} )} + 2

Solution steps

\frac{d y}{d x} = (y - 2)^{4}

Solve separable ODE:

y = - 3 \frac{1}{3 ( x + c _{1} )} + 2

y = - 3 \frac{1}{3 ( x + c _{1} )} + 2

\frac{d p}{d t} = t^{2} p - 6 p + t^{2} - 6

sin (x) d x + \frac{d y}{y} = 0

(x^{2} - x + 1) y^{^{'}} + 4 (1 - 2 x) y = 0

x^{2} (x d y + y d x) = 4 x d y - 4 y d x

\frac{d y}{d x} = - 800 y

What is the solution for (dy)/(dx)=(y-2)^4 ?
The solution for (dy)/(dx)=(y-2)^4 is y=-\sqrt[3]{1/(3(x+c_{1))}}+2