What is the solution for (dy)/(dt)= t/(y-t^2y),y(0)=4 ?

The solution for (dy)/(dt)= t/(y-t^2y),y(0)=4 is y=sqrt(-ln(1-t^2)+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)= t/(y-t^2y),y(0)=4

\frac{d y}{d t} = \frac{t}{y - t ^{2} y}, y (0) = 4

y = - ln (1 - t^{2}) + 16

Solution steps

\frac{d y}{d t} = \frac{t}{y - t ^{2} y}

Solve separable ODE:

y = - ln (1 - t^{2}) + 16

y = - ln (1 - t^{2}) + 16

x \frac{d y}{d x} = e^{6 y + x}, x > 0

\frac{d N}{d t} = k N (t)

\frac{d v}{d t} + 2 v = 32

\frac{d x}{d t} = 5 x - 3, x (2) = 1

\frac{d y}{d t} = a y + b

What is the solution for (dy)/(dt)= t/(y-t^2y),y(0)=4 ?
The solution for (dy)/(dt)= t/(y-t^2y),y(0)=4 is y=sqrt(-ln(1-t^2)+16)