What is the solution for y^'=12xy-2x,y(0)=17 ?

The solution for y^'=12xy-2x,y(0)=17 is y=(101e^{6x^2})/6+1/6

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y^'=12xy-2x,y(0)=17

y^{^{'}} = 12 x y - 2 x, y (0) = 17

y = \frac{101 e ^{6 x^{2}}}{6} + \frac{1}{6}

Solution steps

y^{'} (x) = 12 x y - 2 x

Solve separable ODE:

y = \frac{101 e ^{6 x^{2}}}{6} + \frac{1}{6}

y = \frac{101 e ^{6 x^{2}}}{6} + \frac{1}{6}

\frac{d y}{d t} + 2 y = 3, y (0) = 1

\frac{d y}{d x} + y cos (x) = 6 cos (x)

e^{x} d x - (1 + e^{x}) y d y = 0

\frac{x ^{2}}{y ^{2} - 3} \frac{d y}{d x} = \frac{1}{2 y}

sin (x) cos (y) d x + cos (x) sin (y) d y = 0

What is the solution for y^'=12xy-2x,y(0)=17 ?
The solution for y^'=12xy-2x,y(0)=17 is y=(101e^{6x^2})/6+1/6