What is the solution for v^2y^2dy+vy^3dv+2v^2y^2dy+y^2dy=0 ?

The solution for v^2y^2dy+vy^3dv+2v^2y^2dy+y^2dy=0 is y=(c_{1})/(\sqrt[6]{3v^2+1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^2y^2dy+vy^3dv+2v^2y^2dy+y^2dy=0

v^{2} y^{2} d y + v y^{3} d v + 2 v^{2} y^{2} d y + y^{2} d y = 0

y = \frac{c _{1}}{6 3 v ^{2} + 1}

Solution steps

v^{2} y^{2} d y + v y^{3} d v + 2 v^{2} y^{2} d y + y^{2} d y = 0

Solve separable ODE:

y = \frac{c _{1}}{6 3 v ^{2} + 1}

y = \frac{c _{1}}{6 3 v ^{2} + 1}

\frac{d y}{d x} = 3 y - 1

\frac{d x}{d y} = e^{2 x + 3 y}

(x y - 2 x + 4 y - 8) d y = (x y + 3 x - y - 3) d x

y^{^{'}} + 5 y = 20

y^{^{'}} = y^{2} (x + 1)

What is the solution for v^2y^2dy+vy^3dv+2v^2y^2dy+y^2dy=0 ?
The solution for v^2y^2dy+vy^3dv+2v^2y^2dy+y^2dy=0 is y=(c_{1})/(\sqrt[6]{3v^2+1)}