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Popular >

y^'-xy=5x

Solution

y^{^{'}} - x y = 5 x

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} - 5

Solution steps

y^{'} (x) - x y = 5 x

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 5

y = e^{\frac{x ^{2}}{2} + c_{1}} - 5

Popular Examples

yln(x) d/(dy)(x)=((y+1)/x)^2,y=5,x=4

y ln (x) \frac{d}{d y} (x) = (\frac{y + 1}{x})^{2}, y = 5, x = 4

(dy)/(dx)=(2x+xy^2)/(3y+yx^2)

\frac{d y}{d x} = \frac{2 x + x y ^{2}}{3 y + y x ^{2}}

y^'= 1/2 xsqrt(1-16y^2),y(0)=0

y^{^{'}} = \frac{1}{2} x 1 - 16 y^{2}, y (0) = 0

y^'=4y^{-2}(x^6+x^4+x^2),y(0)=0

y^{^{'}} = 4 y^{- 2} (x^{6} + x^{4} + x^{2}), y (0) = 0

(dy)/(dx)=-x^5y^2

\frac{d y}{d x} = - x^{5} y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'-xy=5x ?
The solution for y^'-xy=5x is y=e^{(x^2)/2+c_{1}}-5