What is the solution for (dy)/(dx)=e^{x-y},y(0)=ln(3) ?

The solution for (dy)/(dx)=e^{x-y},y(0)=ln(3) is y=ln(e^x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=e^{x-y},y(0)=ln(3)

\frac{d y}{d x} = e^{x - y}, y (0) = ln (3)

y = ln (e^{x} + 2)

Solution steps

\frac{d y}{d x} = e^{x - y}

Solve separable ODE:

y = ln (e^{x} + 2)

y = ln (e^{x} + 2)

15 x^{2} y + 3 x^{3} y^{^{'}} - 24 y = 0, y (1) = 1

\frac{d y}{d x} y sin (x^{2}) = x sin (y^{2})

y^{^{'}} = 2 y + 4

y^{^{'}} = \frac{1}{2} y^{3}, y (1) = 4

\frac{d y}{d x} = \frac{3 x ^{2}}{1 - 2 y}

What is the solution for (dy)/(dx)=e^{x-y},y(0)=ln(3) ?
The solution for (dy)/(dx)=e^{x-y},y(0)=ln(3) is y=ln(e^x+2)