en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(1+x)/y ,y(0)=1

Solution

y^{^{'}} = \frac{1 + x}{y}, y (0) = 1

Solution

y = x + 1

Solution steps

y^{'} (x) = \frac{1 + x}{y}

Solve separable ODE:

y = x + 1

y = x + 1

Popular Examples

(y-(xdy)/(dx))=3(1-(x^2dy)/(dx))

(y - \frac{x d y}{d x}) = 3 (1 - \frac{x ^{2} d y}{d x})

sqrt(x)(dy)/(dx)=e^{8y+sqrt(x)},x>0

x \frac{d y}{d x} = e^{8 y + x}, x > 0

y^'=(x^3y)/(x^4+1)

y^{^{'}} = \frac{x ^{3} y}{x ^{4} + 1}

8xy^3dx+12x^2y^2dy=0

8 x y^{3} d x + 12 x^{2} y^{2} d y = 0

(dy)/(dx)+3y=0,y>0

\frac{d y}{d x} + 3 y = 0, y > 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=(1+x)/y ,y(0)=1 ?
The solution for y^'=(1+x)/y ,y(0)=1 is y=x+1