What is the solution for (dy)/(dx)+x^4y=4x^4 ?

The solution for (dy)/(dx)+x^4y=4x^4 is y=e^{-(x^5)/5+c_{1}}+4

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(dy)/(dx)+x^4y=4x^4

\frac{d y}{d x} + x^{4} y = 4 x^{4}

y = e^{- \frac{x ^{5}}{5} + c_{1}} + 4

Solution steps

\frac{d y}{d x} + x^{4} y = 4 x^{4}

Solve separable ODE:

y = e^{- \frac{x ^{5}}{5} + c_{1}} + 4

y = e^{- \frac{x ^{5}}{5} + c_{1}} + 4

x^{^{'}} = \frac{x ^{2} + x}{2 x + 1}, x (0) = 1

sec^{2} (x) d x + 1 - y d y = 0

y - x y^{^{'}} = 1992 (1 + x^{2} y^{^{'}})

sin (x) \frac{d y}{d x} + cos (x) y = 0

(x - 1) y^{^{'}} = 4 - y^{2}

What is the solution for (dy)/(dx)+x^4y=4x^4 ?
The solution for (dy)/(dx)+x^4y=4x^4 is y=e^{-(x^5)/5+c_{1}}+4