What is the solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 ?

The solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 is y=-(cos(x))/(e^{x^3)}+2/(e^{x^3)}

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(dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1

\frac{d y}{d x} + 3 x^{2} y = sin (x) e^{- x^{3}}, y (0) = 1

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

Solution steps

\frac{d y}{d x} + 3 x^{2} y = sin (x) e^{- x^{3}}

Solve linear ODE:

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

\int - 9 x^{5} e^{x^{6}} d x

x \to 5 - lim (\frac{3 x}{2 x + 10})

\int (20 x + 3) d x

\frac{d}{d x} ((arctan (3 x))^{2})

f (x) = \frac{8}{x + 3}, 2

What is the solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 ?
The solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 is y=-(cos(x))/(e^{x^3)}+2/(e^{x^3)}