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Popular >

y^'=y^2+4

Solution

y^{^{'}} = y^{2} + 4

Solution

y = 2 tan (2 t + c_{1})

Solution steps

y^{'} (t) = y^{2} + 4

Solve separable ODE:

y = 2 tan (2 t + c_{1})

y = 2 tan (2 t + c_{1})

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Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2+4 ?
The solution for y^'=y^2+4 is y=2tan(2t+c_{1})