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Popular >

xy^'-y=y^2

Solution

x y^{^{'}} - y = y^{2}

Solution

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Solution steps

x y^{'} (x) - y = y^{2}

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Popular Examples

y^'=((x-2)^2)/y ,y(0)=1

y^{^{'}} = \frac{( x - 2 ) ^{2}}{y}, y (0) = 1

(dy)/(dx)=-4/4 x^4y^2

\frac{d y}{d x} = - \frac{4}{4} x^{4} y^{2}

(dy)/(dx)-y/x =0

\frac{d y}{d x} - \frac{y}{x} = 0

dy=(e^{3x+2y})dx

d y = (e^{3 x + 2 y}) d x

sqrt(x)(dy)/(dx)=e^{10y+sqrt(x)}

x \frac{d y}{d x} = e^{10 y + x}

Frequently Asked Questions (FAQ)

What is the solution for xy^'-y=y^2 ?
The solution for xy^'-y=y^2 is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}